dfinite integration
回答 (1)
2011-04-08 5:52 am
✔ 最佳答案
If f(a-x)=-f(x), show that ∫(fx)dx [0,a] =0f(a-x) = -f(x)
Integrate both side,
∫f(a-x)dx = -∫f(x)dx
-∫f(a-x)d(a-x) = -∫f(x)dx
∫f(a-x)d(a-x) = ∫f(x)dx
Let g(x) = ∫f(x)dx
g(a-x) = g(x)
Put x = a, g(a-a) = g(a) => g(a) = g(0)
Hence, ∫[0,a]f(x)dx = 0
參考: Hope the solution can help you^^”
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