高手進 form 2 maths

2011-04-06 1:25 am
Make the letter in the brackets be the subject of the formulae
4a.K=(b-2)A+a
4b.s=[(u+v)t]/2
5b.S=180(n-2)
6b.A=a/(1-r)
7a.m/2=(2n+3)/3

回答 (3)

2011-04-10 10:06 am
✔ 最佳答案

4a. K = (b - 2)A + a
   K - a = (b - 2)A
   b - 2 = (K - a) / A
   b = 2 + (K - a) / A

4b. s = [(u + v)t] / 2
   2s = (u + v)t
   u + v = 2s / t

5b. S = 180(n - 2)
   n - 2 = S / 180
   n = 2 + S / 180

6b. A = a / (1 - r)
   1 - r = a/A
   r = 1 - a/A

7a. m / 2 = (2n + 3) / 3
   2n + 3 = 3m / 2
   2n = 3(m / 2 - 1)
   n = 3(m / 2 - 1) / 2
2011-04-13 4:44 am
4a.K=(b-2)A+a
K-a=(b-2)A
(K-a)/A=b-2"
[(K-a)/A]+2=b
b=[(K-a)/A]+2

4b.s=[(u+v)t]/2
2s=(u+v)t
2s/t=u+v"

5b.S=180(n-2)
S/180=n-2"
(S/180)+2=n
n=(S/180)+2

6b.A=a/(1-r)
A(1-r)=a
1-r=a/A"
-r=-1+(a/A)
r=-[-1+(a/A)]
r=1-(a/A)

7a.m/2=(2n+3)/3
(m/2)3=2n+3
3m/2=2n+3"
(3m/2)-3=2n
[(3m/2)-3]/2=n
n=[(3m/2)-3]/2

***此數是主項變換,見 " 則是括弧內為主項的答案,再下的則是以未知數為主項的答案。
2011-04-06 5:18 am
where's the brackets?


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