証明
(1)C(n,0)+(1/2)*C(n,1)+(1/3)*C(n,2)+...+【1/(n+1)】*C(n,n)=【1/(n+1)】*【2^(n+1)-1】(2) C(n,0)-(1/2)*C(n,1)+(1/3)*C(n,2)-...+(-1)^n【1/(n+1)】*C(n,n)=【1/(n+1)】
收錄日期: 2021-04-26 14:06:14
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110402000016KK00440