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抛物线y²-2x+4y+6=0的对称轴方程?
回答 (3)
2011-04-01 4:29 pm
✔ 最佳答案
2x = y^2 + 4y + 62x = (y + 2)^2 + 2
x = (y + 2)^2/2 + 1
So the axis of symmetry is y + 2 = 0, or y = - 2.
2011-04-03 9:27 am
对称轴方程=-b/2a
2011-04-01 6:31 pm
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110401000051KK00200