呢條數要點計

2011-04-01 4:57 am

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回答 (1)

2011-04-01 5:14 am
✔ 最佳答案
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2011-03-31 21:17:26 補充:
修正,中間幾行漏了數字2
=√x/2 (1 – x - 2√x √(1 - 2x))
=√x/2 (1 - 2x - 2√x √(1 - 2x) + x)
=√x/2 ([√(1 - 2x)]^2 - 2√x √(1 - 2x) + [√x]^2 )
=√x/2 (√(1 - 2x) - √x)^2 ≥ 0


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