Calculate the molar H+ (aq) ion concentration for...
5.2 = −log [H+(aq)]
8.4 = −log [H+(aq)]
3.68 = −log [H+(aq)]
我想問點樣禁個calculator? 點樣可以把−log 移去另一邊得番 [H+(aq)] 係右邊?
Ph calculation
2011-03-29 4:25 am
回答 (1)
2011-03-29 4:34 am
✔ 最佳答案
5.2 = −log [H+(aq)]−5.2 = log [H+(aq)]
[H+(aq)]=10^ −5.2
Similarly
8.4 = −log [H+(aq)]
[H+(aq)]=10^-8.4
3.68 = −log [H+(aq)]
[H+(aq)]=10^-3.68
2011-03-28 20:36:25 補充：
calculator
shift , log
=10^x
收錄日期: 2021-04-13 17:53:07
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110328000051KK01215