3x^2m-3n+2+4y^1/4m-2n+6=7求m和n
回答 (2)
2011-03-28 5:01 am
✔ 最佳答案
3x^(2m – 3n + 2) + 4y^(1/4 m – 2n + 6) = 7為二元一次方程,2m – 3n + 2 = 1…(1)1/4 m –2n + 6 = 1…(2)8×(2) – (1)=> – 13n + 46 = 7–13n = –39 => n = 3代入(1), 2m – 9 + 2 = 1 => m = 4
2011-03-31 9:38 pm
x^0 and y^0 are 1, so the equations should be
2m-3n+2=0 and
1/4m-2n+6=0
But m is not an integer. You can try on your own. Always remember any number to the power of 0 is 1.
2m-3n+2=0 and
1/4m-2n+6=0
But m is not an integer. You can try on your own. Always remember any number to the power of 0 is 1.
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