Gravitation and E-field

2011-03-28 12:50 am

圖片參考:http://imgcld.yimg.com/8/n/HA00270495/o/701103270064913873395881.jpg

By taking right as +ve,
if the G-field against distance and potential against distance between the earth and the moon is shown above,
Q: Is my deduction of E-field against distance and potential against distance between the -ve charge and the +ve charge correct?
更新1:

Graph of E-field against distance is taking right as -ve

回答 (1)

2011-03-30 4:41 am
✔ 最佳答案
The shape of the curves are basically right.

For the earht-moon curves, the point where the gravitational forces from the earth and moon cancel each other should be closer to the moon.

For the two-charge curves, I suppose the two charges are not equal in magnitudes, as the field intensity near the +ve charge is shown to be weaker than that near the -ve charge. Hence, the point of zero potential should be closer to the +ve charge.


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