limits and derivatives 3q
2011-03-26 8:05 am
圖片參考：http://imgcld.yimg.com/8/n/HA00133515/o/701103260000913873395070.jpg
I am just a beginner, so explain slowly please.
Thank you!
From the formula above,
how do we find 1. (or using other method)
Next
explain, how to find ('exponents with exponents')
using ln to perform the answer and then solve 2.
Last one,
prove 3. write down the formula used , such as L'hopital Rule, trigo identities...)
Once again, explain it slowly so i can get the idea. Thanks.
回答 (2)
2011-03-26 6:28 pm
2011-03-26 8:13 pm
lim(x->0) x/sinx
= lim(x->0) 1/(sinx / x)
= [lim(x->0) 1] / [lim(x->0) (sinx / x)]
= 1
No L'Hospital rule is required.
= lim(x->0) 1/(sinx / x)
= [lim(x->0) 1] / [lim(x->0) (sinx / x)]
= 1
No L'Hospital rule is required.
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