更新1:
Can you explain more how ∫x(2^x) dx = (1/ln2) ∫ x d(2^x)
Integration by parts
回答 (1)
2011-03-26 5:42 am
✔ 最佳答案
∫ x(2^x) dx= (1/ln2) ∫ x d(2^x)
= (1/ln2)[x(2^x) - ∫ (2^x) dx]
= (1/ln2)[x(2^x) - (1/ln2)(2^x)]
= 2^x(xln2 - 1)/(ln2)^2
收錄日期: 2021-04-23 18:28:56
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https://hk.answers.yahoo.com/question/index?qid=20110325000051KK01068