Find dy/dx.
(b) Hence evaluate ∫(sinx)^n dx
更新1:
y = [(sinx)^(n-1)] * cosx
Integration
2011-03-24 9:18 pm
(a) Let y = (sinx)^(n-1) cosx, where n is a constant
Find dy/dx.
(b) Hence evaluate ∫(sinx)^n dx
Find dy/dx.
(b) Hence evaluate ∫(sinx)^n dx
回答 (1)
2011-03-25 8:18 am
收錄日期: 2021-04-22 00:53:52
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