10x+y=3(x+y)...............(1)
{
10x+y+9=4(x+y)..............(2)
可用加減或代入消元法
請註明步驟
希望大家幫幫忙 >.<
求救!二元一次方程 (加減,代入消元法)
2011-03-23 1:52 am
回答 (1)
2011-03-23 1:57 am
✔ 最佳答案
(10x + y) = 3(x + y) ......(1)(10x + y) + 9 = 4(x + y) ......(2)(2) - (1) :9 = x + y .....(3) , 代入 (1) :10x + y = 3(9) 10x + y = 27 ......(4)(4) - (3) :9x = 27 - 9
9x = 18
x = 2代入 (3) :9 = 2 + y ,y = 7答 : x = 2 , y = 7
收錄日期: 2021-04-21 22:20:50
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110322000051KK00722