integration x1

∫ 2arcsin(x/5) dx
= ∫ 10y(cosy) dy
= 10y(siny) - 10∫ siny dy
= 10y(siny) + 10cosy + C (where C is a constant)
= 2arcsin(x/5) + 2√(25 - x^2) + C

Reference:

http://integrals.wolfram.com/index.jsp

2011-03-20 23:38:02 補充：
I miss a x in the last line. It should be 2x arcsin(x/5) + 2√(25 - x^2) + C

Sorry

As the following

圖片參考：http://upload.trend.hk/images/1300632267.JPG