✔ 最佳答案
V = π ∫ [f(x)]^2 dx
By symmetry, we only need to consider the positive value of x
From x^2 + y^2 = r^2
y^2 = r^2 - x^2 and the largest value of x is r
So, V
= 2π ∫ [f(x)]^2 dx [from 0 to r]
= 2π ∫ (r^2 - x^2) dx [from 0 to r]
= 2π(r^3 - x^3/3 | [0,r])
= 2π(r^3 - r^3/3)
= 4πr^3/3