lim(x→∞)1/((4x)-(開方16x^2-3x))
己知(開方16x^2-3x)/x=4
/是分數,開方是整個(16x^2-3x),^是次方
求極限lim(x→∞)
2011-03-21 2:45 am
回答 (2)
2011-03-21 2:53 am
2011-03-21 7:38 am
lim(x->∞)_1/[4x－√(16x^2－3x)]
=lim(x->∞)_1/[4x－√(16x^2－3x+9/64)]
=lim(x->∞)_1/[4x－(4x－3/8)]
=lim(x->∞)_1/(3/8)
=8/3
=lim(x->∞)_1/[4x－√(16x^2－3x+9/64)]
=lim(x->∞)_1/[4x－(4x－3/8)]
=lim(x->∞)_1/(3/8)
=8/3
收錄日期: 2021-04-23 23:25:22
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110320000051KK01091