Determine whether log59/log4 is greater than log41/log3.
Hint: if a>b>0, then loga/logx > logb/logx, where x>1
comparision of log
2011-03-19 6:24 am
回答 (1)
2011-03-19 6:37 am
✔ 最佳答案
log59 / log4= log(4³ - 5) / log4< log 4³ / log4= 3;log41 / log3= log(3³ + 14) / log3> log 3³ / log3= 3Therefore log59 / log4 < 3 < log41 / log3log41 / log3 is greater than log59 / log4.
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