✔ 最佳答案
I've figured out some sorts of 'skill'. Let's see if it works:
Cl2O + H2O--> 2HClO
2ClO2+ H2O--> HClO+ HClO3
Cl2O6+ H2O --> HClO3 + HClO4
Cl2O7+ H2O --> 2HClO4
Can you see the pattern?
If the no. of 'O' atom on the left hand side is an even number, the products have the same no. of 'O'. Eg, 'Cl2O + H2O' = 2 'O' atoms. Each product formed can share one 'O'
If the no. of 'O' atom on the left hand side is a odd number, the products share the 'O' atoms with one of them gets one more of which. Eg, 'Cl2O6+ H2O' = 7 'O' atoms. One product gets 3 and one gets 4 'O' atoms as the result.
Um... For other reactions, more time is needed ^^" or you can try to find out the patterns of reaction and work out your own methods. I don't know if it works. Please see. CHeer you up! ;)
