更新1:
the equation is actually y = x^3 + ax^2 + bx + c
APPLICATION OF DIFFERENTIATION
2011-03-17 10:18 pm
1. Given that (0,0) and (1,2) are two points on curve y = x^3 +ax^2 +c, where a, b and c are constants, the slope of the tangent at point (1,2) is -1, find values of a,b and c.
回答 (1)
2011-03-17 10:55 pm
✔ 最佳答案
where is b??2011-03-17 14:55:30 補充：
Suppose the equation is y=ax^3+bx^2+c:
圖片參考：http://i707.photobucket.com/albums/ww74/stevieg90/ScreenHunter_04Mar171453.gif
2011-03-17 23:55:47 補充：
Updated sol. has been uploaded, plx take a look!
2011-03-19 14:15:38 補充：
My sol. is updated and you can check it, thx!
收錄日期: 2021-04-22 00:54:22
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110317000051KK00375