TRIGONOMETRY

2011-03-17 4:06 am
1. SOLVE IT FOR 0<=X<=兀

sin2x+sin3x=0


2. find cos3θ IN TERMS OF cosθ

回答 (1)

2011-03-17 4:16 am
✔ 最佳答案
sin2x + sin3x = 0

2sin(5x/2) cos(x/2) = 0sin(5x/2) = 0 or cos(x/2) = 05x/2 = 0, 180, 360,

x/2 = 90,

So, x = 0,72,144,180,

2 cos3θ

= cos(2θ + θ)

= cos2θcosθ - sin2θsinθ

= cosθ(2cos^2θ - 1) - 2sinθ^2 cosθ

= cosθ(2cos^2θ - 1) - 2(1 - cosθ^2) cosθ

= 4cos^3θ - 3cosθ


收錄日期: 2021-04-26 14:54:53
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110316000051KK00995

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