Find the particular solution 1

(a) I can only tell you how to draw it since I don't have the necessary software. For exapmle, at (1,1) ,dy/dx = -2 and then you draw a small line segment at (1,1) with slope -2 is OK.

(b) At (1,-1) dy/dx = 2
So, the equation is y + 1 = 2(x - 1)
Sub. x = 1.1, y = -0.8

(c) dy/dx = -2x/y

-y dy = 2x dx

-y^2/2 = x^2 + C

Sub. (1,-1) C = -3/2 and so y = -√(3x - 2)