PROVE THE FOLLOWINGS
TAN A+TAN B = SEC^2 A-SEC^2 B/TAN A-TAN B
F.4 TRIGONOMETRY M2
2011-03-14 6:52 am
回答 (2)
2011-03-14 7:03 am
✔ 最佳答案
SEC^2 A-SEC^2 B/(TAN A-TAN B)=[(TAN^2 A+1)-(TAN^2 B+1)]/(TAN A-TAN B)
=(TAN^2 A-TAN^2 B)/(TAN A-TAN B)
=[(TAN A+TAN B)(TAN A-TAN B)]/(TAN A-TAN B)
=TAN A+TAN B
2011-03-16 9:29 pm
SEC^2 A-SEC^2 B/(TAN A-TAN B) =[(TAN^2 A+1)-(TAN^2 B+1)]/(TAN A-TAN B) =(TAN^2 A-TAN^2 B)/(TAN A-TAN B) =[(TAN A+TAN B)(TAN A-TAN B)]/(TAN A-TAN B) =TAN A+TAN B
I hope this answer can help you!!!!
I hope this answer can help you!!!!
參考: mine
收錄日期: 2021-04-22 00:53:52
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