請問呢條equation點計,計極計唔到個答案
5^x * 25^2x+1 = 1
求X的值
有關Logarithmic Equations 嘅問題
2011-03-12 9:51 pm
回答 (2)
2011-03-12 10:00 pm
✔ 最佳答案
5^x * 25^(2x+1) = 1 5^x * (5²)^(2x+1) = 15^x * 5^[2(2x+1)] = 15^x * 5^(4x+2) = 15 ^ (x + 4x+2) = 15 ^ (5x+2) = 15 ^ (5x+2) = 5 ^ 05x + 2 = 0x = - 2/5
2011-03-13 12:10 am
5^x × 25^2x+1 = 1 5^x × 5^4x+2=15^5x+2=1(5x+2)log5=log1(5x+2)log5=05x+2=0x=-2/5
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收錄日期: 2021-04-21 22:19:28
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110312000051KK00578