If 2cos^2 x - sin2x -1 =0 where 0<=x<=兀, find the values of x
If 2+6sinAcosA+4sin^2 A-4sin^4 A =0, where 0<=A<2兀, find the value of A
solve the following equations for 0<=x<=2兀
(A) cos2x+sinx=0 (B) 2sin^2 x-sin2x=2
收錄日期: 2021-04-23 23:22:35
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https://hk.answers.yahoo.com/question/index?qid=20110312000051KK00456