✔ 最佳答案
a) By the given △BDE ≡ △FDC , we have :BD = FD ......(1)CD = ED ......(2)ㄥBDE = ㄥFDC
ㄥBDE - ㄥFDE = ㄥFDC - ㄥFDE
ㄥBDF = ㄥCDE .......(3)By (1) , (2) , (3) :
△BDF and △CDE both are isos. Δ with the same upper angle.So△BDF ~ △CDE (S.A.S.)Therefore ㄥFBD = ㄥCED since the base ㄥ of a pair similar isos. Δ are equal.And hence :ABDE is a cyclicquad (ext.∠= int. opp.∠)
b)Similarly ,ㄥDCE = ㄥDFB ,CDFA is a cyclicquad (ext.∠= int. opp.∠)