Solve the following equation :
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a natural log question
2011-03-05 7:41 pm
回答 (1)
2011-03-05 7:55 pm
✔ 最佳答案
e^(2x+1) + 2e^(x+2) - 3 = 0e e^(2x) + (2e²) (e^x) - 3 = 0e (e^x)² + 2e² (e^x) - 3 = 0e^x = { - 2e² ± √ [(2e²)² - 4e(-3)] } / (2e)e^x = - e ± (1/e)√ [e(e³ + 3)] e^x = 0.19594 or - 5.63250x = In 0.19594 or In - 5.63250 (rejected)x = - 1.63 (3 sig. fig.)
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https://hk.answers.yahoo.com/question/index?qid=20110305000051KK00399