a natural log question

e^(2x+1) + 2e^(x+2) - 3 = 0e e^(2x) + (2e²) (e^x) - 3 = 0e (e^x)² + 2e² (e^x) - 3 = 0
e^x = { - 2e² ± √ [(2e²)² - 4e(-3)] } / (2e)e^x = - e ± (1/e)√ [e(e³ + 3)] e^x = 0.19594 or - 5.63250x = In 0.19594 or In - 5.63250 (rejected)x = - 1.63 (3 sig. fig.)