proof
2^k -1 + 2^k = 2^ (k+1) - 1
proof
2- 1/ 2^(k-1) +(1/2)^k = 2- 1/ 2^ (k+1-1)
maths f.4
2011-03-04 3:42 am
回答 (1)
2011-03-04 3:54 am
✔ 最佳答案
2^k - 1 + 2^k= 2^k + 2^k - 1= 2(2^k) - 1= 2^(k+1) - 1;2 - 1/2^(k-1) + (1/2)^k= 2 - 1/2^(k-1) + (1/2^(k-1))(1/2)= 2 - [1/2^(k-1)] (1 - 1/2)= 2 - [1/2^(k-1)] (1/2)= 2 - 1/2^(k + 1 - 1)
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