F.5 variations

2011-02-28 7:09 am
It is given that p varies directly as the cube of q when r remains as a constant, and varies inversely as the square root of r when q remains as a constant. When q=2 and r=9,p=16
a.Express p in terms of q and r.
b.Find the value of r when p=12 and q=1

回答 (1)

2011-02-28 7:43 am
✔ 最佳答案
(a) Let p = Aq^3/√r

Sub. q=2 and r=9,p=16

16 = 8A/3

A = 6

p = 6q^3/√r

(b) 12 = 6/√r

r=1/4


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