✔ 最佳答案
Let d be the spacing between successive lines on the grating, then:
For the first order:
d sin θR = 7 x 10-7
d sin θV = 4 x 10-7
So:
d(sin θR + sin θV) = 11 x 10-7
2d sin [(θR + θV)/2] cos [(θR - θV)/2] = 11 x 10-7
2d sin [(θR + θV)/2] cos 15 = 11 x 10-7 ... (1)
d(sin θR - sin θV) = 3 x 10-7
2d sin [(θR - θV)/2] cos [(θR + θV)/2] = 3 x 10-7
2d sin 15 cos [(θR + θV)/2] = 3 x 10-7 ... (2)
Using (1) to divide (2):
tan [(θR + θV)/2]/tan 15 = 11/3
tan [(θR + θV)/2] = (11 tan 15)/3 = 0.982
(θR + θV)/2 = 44.5
Sub this into either (1): 2d sin 44.5 cos 15 = 11 x 10-7d = 8.12 x 10-7 mHence in 1 mm, no. of lines is:
10-3/(8.12 x 10-7) = 1230
2011-02-21 21:57:22 補充:
θR - θV = 30 度
(θR - θV)/2 = 15 度