maths solution please

👨🏻‍🏫 學術台數學

用戶216248

2011-02-20 6:14 pm

12(c2+2)+2(c2+2)2-18
Can anyone solve this??? Try few times and have asked friends to do it, still different from the answer given.

更新1:

the smaller size of 2 is "square"

更新2:

need to be factorized.

回答 (2)

ShikaP

2011-02-20 6:54 pm

✔ 最佳答案

sol
12(c^2+2)+2(c^2+2)^2-18
= 12c^2+24+2(c^4+4c^2+4)-18
= 2c^4 + 20c^2 + 14

2011-02-20 13:59:23 補充：
12(c^2+2)+2(c^2+2)^2-18
= 12c^2+24+2(c^4+4c^2+4)-18
= 2c^4 + 20c^2 + 14
= 2c^4 + 16c^2 + 14+4c^2
=2(c^4+8c^2+7)+4c^2
=2(c^2+7)(c^2+1)+4c^2
=2[(c^2+7)(c^2+1)+2c^2]

2011-02-20 16:23:45 補充：
if 知識就是力量 ( 碩士級 1 級 ) is right...
12(c^2+2)+2(c^2+2)^2+18
= 12c^2+24+2(c^4+4c^2+4)+18
=2c^2+20c^2+50
=2(c^4+10c^2+25)

2011-02-20 16:40:32 補充：
＊例行提醒

請勿在得到答案後移除問題

參考: marked by miruru

👍 0 👎 0

知識就是力量

2011-02-20 11:56 pm

Is 12(c^2 + 2) + 2(c^2 + 2)^2 - 18
or 12(c^2 + 2) + 2(c^2 + 2)^2 + 18?

👍 0 👎 0

收錄日期: 2021-04-23 23:27:23
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110220000051KK00341

檢視 Wayback Machine 備份