Find the equation of the tangent to the circle C at the point A.
A(3,-5) and C: (x+2)^2+y^2 =50
F.5 Maths(Equation of Circle)
2011-02-20 8:07 am
回答 (2)
2011-02-20 8:18 am
✔ 最佳答案
As follows:圖片參考：http://i707.photobucket.com/albums/ww74/stevieg90/ScreenHunter_07Feb192337.gif
2011-02-20 8:21 am
Find the equation of the tangent to the circle C at the point A.
A(3，－5) and C：(x+2)^2+y^2 =50
Sol
(3+2)^2+(－5)^2=50
So
A 在圓 C圓周上
圓心O(－2，0)
OA直線方程式：x+y+2=0
X－y+k=0
3－(－5)+k=0
k=－8
x－y－8=0
A(3，－5) and C：(x+2)^2+y^2 =50
Sol
(3+2)^2+(－5)^2=50
So
A 在圓 C圓周上
圓心O(－2，0)
OA直線方程式：x+y+2=0
X－y+k=0
3－(－5)+k=0
k=－8
x－y－8=0
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