The distance (d km) to the horizon varies directly as the square root of the height (h m) of the observer above the ground. It is known that from the branch of a tree 4m above the ground, the farthest distance a person can see is 5.2km.
1) What is the farthest distance that a helicopter pilot 625m above the ground can see?
2) What is the height of a person above the ground if the farthest distance can see is 3.38km?
Variation
2011-02-20 1:28 am
回答 (1)
2011-02-20 1:37 am
✔ 最佳答案
1)d=k√h, where k is a constant
It is known that from the branch of a tree 4m above the ground, the farthest distance a person can see is 5.2km.
=> When h=4, d=5.2
5.2=k√4 => 5.2=2k => k=2.6
Hence, we have d=2.6√h
When h=625, d=2.6√625=2.6(25)=65
So, the farthest distance=65km
2)
For d=3.38,
3.38=2.6√h
√h=1.3
h=1.69
So, the height is 1.69m
收錄日期: 2021-04-22 00:54:38
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https://hk.answers.yahoo.com/question/index?qid=20110219000051KK00886