show that
sin x <= x for all x>0
limit
2011-02-19 9:39 pm
回答 (1)
2011-02-19 9:49 pm
✔ 最佳答案
Consider f(x) = x - sinxf'(x) = 1 - cosx > 0 for x > 0
So f(x) is a strictly increasing function for x > 0
As f(0) = 0
So f(x) = x - sinx > 0 for x > 0
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