help .. 分式方程組 x5
2011-02-10 9:03 am
回答 (2)
2011-02-10 9:43 pm
✔ 最佳答案
As follows:圖片參考：http://i707.photobucket.com/albums/ww74/stevieg90/ScreenHunter_03Feb101342.gif
2011-02-10 10:47 am
1/(x+y)+1/y=2-----------------1
{
1/(x+y)-1/y=0------------------2
1-2,
1/(x+y)-1/(x+y)+1/y-(-1/y)=2-0
2/y=2
2=2y
y=1
sub.y=1 into 1
1/(x+1)+1/1=2
1/(x+1)=1
1=x+1
x=0
{
1/(x+y)-1/y=0------------------2
1-2,
1/(x+y)-1/(x+y)+1/y-(-1/y)=2-0
2/y=2
2=2y
y=1
sub.y=1 into 1
1/(x+1)+1/1=2
1/(x+1)=1
1=x+1
x=0
參考: myself
收錄日期: 2021-04-22 00:55:27
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110210000051KK00087