1.
27(5^x)-125(3^x)=0
Solve the equation.
2.
5^x=0.5
5^(-kx)=8
Find the value of k.
Show steps, Thank you very much!
F4 Exp. Functions
2011-02-09 4:15 am
回答 (1)
2011-02-09 4:25 am
✔ 最佳答案
1.27(5^x)-125(3^x)=027(5^x) = 125(3^x)27/125 = (3^x)/(5^x)27/125 = (3/5)^x(3/5)^3 = (3/5)^xx = 32.5^(-kx)=8(5^x)^(-k) = 80.5^(-k) = 8(2^(-1))^(-k) = 82^k = 82^k = 2^3k = 3
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