曲線y=[(2x^2)/(x+1)]-1
/代表分數
直線3x-2y-3=0是曲線在P的切線,找P的坐標
切線方程(M1)(5點)
2011-02-09 1:01 am
回答 (1)
2011-02-09 1:15 am
✔ 最佳答案
y=[(2x^2)/(x+1)]-1 ....(1){3x-2y-3=0 ....(2)由(2) : 2y = 3x - 3代入 (1)*2 :3x - 3 = (4x^2)/(x+1) - 2(3x - 1)(x + 1) = 4x^23x^2 + 2x - 1 = 4x^2x^2 - 2x + 1 = 0(x - 1)^2 = 0x = 1 , 2y = 3(1)-3y = 0Answer : (1 , 0)
收錄日期: 2021-04-21 22:26:14
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110208000051KK01024