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2011-02-08 3:30 am

2[3y-(4-2y)]=4-2y

回答 (5)

2011-02-08 3:45 am

✔ 最佳答案

2[3y-(4-2y)]=4-2y
2[3y-4+2y]=4-2y
6y-8+4y=4-2y
6y+4y+2y=4+8
12y=12
y=1

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2011-02-08 5:43 am

2[3y-(4-2y)]=4-2y
3y-(4-2y)=2-y
3y-4+2y=2-y
5y-4=2-y
6y-4=2
6y=6
y=1

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2011-02-08 3:45 am

2[3y-(4-2y)]=4-2y
6y-2(4-2y)=4-2y
6y-8+4y=4-2y
12y=12
y=1

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2011-02-08 3:36 am

2[3y-(4-2y)]=4-2y
2(3y-4+2y)=4-2y
6y-8+4y=4-2y
6y+4y-2y=4+8
8y=12
y=12/8
y=1.5

hope I can help you

參考: me

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2011-02-08 3:34 am

2[3y-(4-2y)]=4-2y
2[3y-4+2y] =4-2y
2[5y-4]=4-2y
10y-8=4-2y
12y=12
y=1

參考: myself

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