Please solve the following equation.
4(x-2)4-8(x-2)2-5=0
Clear version:
4(x-2)^4-8(x-2)^2-5=0
Maths Question (Equations)
2011-02-06 2:44 am
回答 (1)
2011-02-06 2:51 am
✔ 最佳答案
For solving the real solutions x, we let u=(x-2)^24(x-2)^4-8(x-2)^2-5=0
4u^2-8u-5=0
(2u-5)(2u+1)=0
u=5/2 or u=-1/2 (rejected as (x-2)^2>=0)
(x-2)^2=5/2
x-2=±√(5/2)
x=2±√(5/2)
x=2±√10/2
Hence, the real solutions are 2±√10/2
收錄日期: 2021-04-22 00:52:21
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110205000051KK00716