Maths(area and volume)

2011-02-05 6:08 am
A test-tube of height 12cm is standing upright on a table.It consists of a cylindrical part of radius 1.5cm and a hemisphere part of the same radius.If 6cm^3 of water is poured into the tube,find the depth of water in the test-tube.
更新1:

The answer is 8.99cm.

更新2:

Re';Godfrey yes,you are right.There are a mistake.I'm sorry.

回答 (1)

2011-02-05 12:04 pm
✔ 最佳答案
Amy, I think there is a typo error. 60 cm^3 of water is poured into the test tube, not 6 cm^3. My calculation is based on 60 cm^3.

Calculation:
The volume of hemisphere = half of a sphere
The volume of hemisphere = (1/2)(4/3)(pi)(r^3) where r = radius
The volume of hemisphere= (1/2)(4/3)(pi)(1.5^3) = 7.068 cm^3

Volume of the cylinder of water = volume of water – volume of hemisphere
Volume of the cylinder of water = 60 cm^3 – 7.068 cm^3 = 52.932 cm^3
Volume of the cylinder of water = (pi) (r^2)(h) where h is height of water in cylinder
52.932 cm^3 = (pi) (r^2)(h)
52.932 cm^3 = (pi) (1.5^2)(h)
h = 52.932 cm^3/ [(pi) (1.5^2)]
h = 52.932 cm^3/ [(3.14159) (2.25 cm ^2)]
h = 7.488 cm

Depth of water = radius of hemisphere + height of water in cylinder
Depth of water = 1.5 cm + 7.488 cm = 8.988 cm

Depth of water in the test-tube = 8.99 cm




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