math F4 Help
回答 (1)
2011-02-04 9:35 pm
✔ 最佳答案
1/(1-x) + ((x-4)(x+2)/(16-x²) / ((x²+2x)/(x²+4x)) = 1/(1-x) + ((x-4)(x+2)/((4-x)(4+x)) / ((x²+2x)/(x²+4x))
= 1/(1-x) - ((x+2)/(x+4)) / ((x²+2x)/(x²+4x))
= 1/(1-x) - ((x+2)/(x+4)) / ( x(x+2)/(x(x+4)) )
= 1/(1-x) - 1
= 1/(1-x) - (1-x)/(1-x)
= x / (1 - x)
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110204000051KK00153