Above the xy-plane and under the surfaces z=1-x^2-2y^2
更新1:
the ans is pi/(2 square root2)
更新2:
why the upper bound and lower bound are not +-square root((1-x^2)/2)
double integra6
2011-02-03 5:22 am
Find the volume of the indicated solid,
Above the xy-plane and under the surfaces z=1-x^2-2y^2
Above the xy-plane and under the surfaces z=1-x^2-2y^2
回答 (1)
2011-02-03 4:35 pm
✔ 最佳答案
http://img593.imageshack.us/img593/3109/49410473.png圖片參考：http://img593.imageshack.us/img593/3109/49410473.png
2011-02-03 22:49:47 補充：
題目看漏了個2字,修正如下:
http://img718.imageshack.us/img718/3231/17203085.png
收錄日期: 2021-04-23 23:26:02
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110202000051KK01036