Physics - Error Measurement

2011-01-24 12:16 am
Physics - Error Measurement

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回答 (2)

2011-01-24 12:54 am
✔ 最佳答案
T = 2π√(m/k)

k = m/[T/(2π)]^2

k = 4π^2m/T^2

if |ΔT/T| = 0.05 and |Δm/m| = 0.04

|Δk/k|

= |Δm/m| + 2|ΔT/T|

= 0.04 + 2(0.05)

= 0.14

The error of the measured k is 14% (D)
2011-01-24 12:58 am
Since k = (2.pi)^2.[m/T^2]
hence, dk/k = dm/m + 2(dT/T)
where dm/m and dT/T are the fractional errors of m and T respectively
but dm/m = 0.04 and dT/T = 0.05

thus, dk/k = 0.04 + 2 x(0.05) = 0.14
Therefore, the percentage errror of k is 14%


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