10.0 g iron ore sample contains iron(III) oxide. If the sample contains 3.3 g of iron, what is the percentage ny mass of iron(III) oxide in the sample?
A 33%
B 47%
C 94%
D100%
I want a good answer, thank you
Chem mole simple question
2011-01-20 4:33 am
回答 (3)
2011-01-21 10:30 pm
✔ 最佳答案
what do you mean by "I want a good answer"? no one here will give you fake answers.
mass of iron = 3.3 g
no. of mole of iron = 3.3/55.8 = 0.0591 mole
formula of iron(III) oxide : Fe2O3
mole ratio of Fe:Fe2O3 = 2:1
thus no. of mole of Fe2O3 = 0.059/2 = 0.0296 mole
molar mass of Fe2O3 = 55.8x2 + 16x3 = 159.6 g/mol
mass of iron(III) oxide = 0.0296 x 159.6 = 4.724 g
percentage by mass = mass of analyte / total mass
= 4.724/10 = 47.2%
2011-01-20 4:44 am
3.3 g of iron
2011-01-20 4:43 am
3.3g of iron(III)oxide or iron?
收錄日期: 2021-04-19 23:54:30
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