Basic Statistic 2

2011-01-19 3:02 am

回答 (1)

2011-01-19 9:43 pm
✔ 最佳答案
(a)
Let S be the event that he will receive a ticket.
P(S) = (40%)(0.2) + (30%)(0.1) + (20%)(0.5) + (10%)(0.2)
= 0.23

(b)
P(L2|S) = P(L2 and S) / P(S)
= (30%)(0.1) / 0.23
= 0.03/0.23
= 3/23


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