Material science

[匿名]

2011-01-15 2:02 am

A steel tie-rod is 6m long and 50mm in diameter when subjected to a tensile load of 250kN (Given: E= 200kN/mm^2)
(i) cross-sectional area in mm^2
(ii) stress
(iii) strain
(iv) increase in length in mm

回答 (2)

用戶25568

2011-01-15 2:13 am

✔ 最佳答案

i)cross section = 50/2 * 50/2 * pi ~ 1885mm2ii) stress = force / area = 250kN / (1885 / 1000000) <== convert to SIstress ~ 132MPaiii) = F / EA 250k / (200k * 1885) ~ 0.068%iv) increase in lenth = length * strain= 60 * 0.00068 ~ 0.041m ~ 41mm

2011-01-14 18:13:31 補充：
i)
cross section = 50/2 * 50/2 * pi ~ 1885mm2

ii) stress = force / area = 250kN / (1885 / 1000000) <== convert to SI
stress ~ 132MPa

iii) = F / EA
250k / (200k * 1885) ~ 0.068%

iv) increase in lenth = length * strain
= 60 * 0.00068 ~ 0.041m ~ 41mm

sorry for the poor format

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用戶78813

2011-01-15 2:18 am

想問一問cross section = 50/2 * 50/2 * pi
Pi係?

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