z= x^2 + 4 y^2 and z=2x
Also, find the equation of the tangent line at (2,0,4) to the curve C of the intersection of the surfaces above.
更新1:
why in the last part, the ans is (2,t,4),not (2,t/2,4)?? THX~~
calculus of vector-valued fun2
2011-01-15 12:05 am
Find the parametric equations of the curve C of intersection of the surface
z= x^2 + 4 y^2 and z=2x
Also, find the equation of the tangent line at (2,0,4) to the curve C of the intersection of the surfaces above.
z= x^2 + 4 y^2 and z=2x
Also, find the equation of the tangent line at (2,0,4) to the curve C of the intersection of the surfaces above.
回答 (1)
2011-01-15 6:49 am
✔ 最佳答案
http://img291.imageshack.us/img291/9573/64446658.png圖片參考：http://img291.imageshack.us/img291/9573/64446658.png
2011-01-15 13:16:29 補充：
(2,t,4) is just the same as (2,t/2,4)
t is a free variable and can take on any real value
even if yu say for example (2,9t,4) it is still the same
Since t is the simplest so I use t instead of t/2
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