Find EF

2011-01-14 7:24 am

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AED,BEC and BFD are straight lines,AB//CD//EF,find EF=?

回答 (1)

2011-01-14 7:38 am
✔ 最佳答案
△DEF~△DAB (A.A.) => EF/AB=DF/DB...(*)
△BEF~△BCD (A.A.) => EF/CD=BF/DB...(**)

(*)+(**):
(EF/AB)+(EF/CD)=(DF/DB)+(BF/DB)
EF[(1/AB)+(1/CD)]=(DF+BF)/DB
EF[(1/24)+(1/16)]=DB/DB
EF[(1/24)+(1/16)]=1
EF=1/[(1/24)+(1/16)]
EF=48/5


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