Given that 1 g H2X contains 1.765x10^22 molecules
a) What is the nouber of mo,es of H2X in 1 g?
b)What is the relative molecular mass of H2X?
c)What is the relative atomic mass of X?
chemistry!(Quick)Reacting mass
2011-01-13 1:11 am
回答 (1)
2011-01-13 2:23 am
✔ 最佳答案
a) No. of moles= 1.765*10^22 / 6.02*10^23 , where 6.02*10^23 is the Avogradro's Constant.
= 0.02932 mol
b) Relative molecular mass
= 1/0.02932
= 34.11
c) Relative atomic mass of X
= 34.11 - 1*2
= 32.11
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