✔ 最佳答案
The wikipedia web page has already told that an excited fluorescent molecule can be de-excited by various competing pathways. It can undergo 'non-radiative relaxation' in which the excitation energy is dissipated as heat (vibrations). The emission of photons in fluorescence is governed by the Kasha-Vavilov Rule, which states that photon emission is expected in appreciable yield only from the lowest excited state, If the difference in energy levels between the first excired state (i.e. lowest excited state) and the ground state gives rise to a photon with energy within the visible light range, the substance exhibit fluorescence. Hence, the emission wavelength in fluorescence is independent of the excitation wavelength.
You could read the explanation on the Kasha-Vavilov Rule in the following web-page:
http://en.wikipedia.org/wiki/Kasha%27s_rule