F.1 Equations in one unknown

2011-01-10 1:59 am
1.) 7[2(x-3)+x]=4[1-3(x+2)]

2.) 3[5(m+2)+m]=2[3(m+4)-1]


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THX.....................

回答 (2)

2011-01-11 12:45 am
✔ 最佳答案
1.)7[2(x-3)+x]=4[1-3(x+2)]
7[2x-6+x] =4[1-(3x+6)]
7(3x-6) =4[1-6-3x]
21x-42 =4(-5-3x)
21x-42 =-20-12x
21x-42+42=-20-12x+42
21x =22-12x
21x+12x =22-12x+12x
33x =22
33x/33 =22/33
x =2/3#

2.)3[5(m+2)+m]=2[3(m+4)-1]
3[5m+10+m]=2[3m+12-1]
3(6m+10) =2(3m+11)
18m+30 =6m+22
18m+30-30 =6m+22-30
18m =6m-8
18m-6m =6m-8-6m
12m =-8
12m/12 =-8/12
m =-2/3#
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參考: 自己
2011-01-10 2:20 am
1) 7[ 2( x - 3 ) + x ] = 4[ 1 - 3( x + 2 ) ]
7( 2x - 6 + x ) = 4( 1 - 3x - 6 )

7( 3x - 6 ) = 4( -5 - 3x )

21x - 42 = -20 - 12x

21x + 12x = -20 + 42

33x = 22

x = 22/33

x = 2/3
===== 2) 3[ 5( m + 2 ) + m ] = 2[ 3( m + 4 ) - 1 ]

3( 5m + 10 + m ) = 2( 3m + 12 - 1 )

3( 6m + 10 ) = 2( 3m + 11 )

18m + 30 = 6m + 22

12m = -8

m = -8/12

m = -2/3
======


Hope I can help you.

參考: Mathematics Teacher Mr. Ip


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