Evaluate the following integral:
∫{(x) tan[(x)(x)] }dx
integration
2011-01-09 3:12 am
回答 (1)
2011-01-09 3:54 am
✔ 最佳答案
Let u=x^2, then du=2xdx∫xtan(x^2)dx
=(1/2)∫tan(u)du
=(1/2)∫[sin(u)/cos(u)]du
=-(1/2)∫d(cos(u))/cos(u)
=-(1/2)ln∣cos(u)∣+constant
2011-01-08 19:55:15 補充：
Hence,
∫xtan(x^2)dx=-(1/2)ln∣cos(x^2)∣+constant
收錄日期: 2021-04-22 00:52:29
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110108000051KK01234